Problem 2.

Problem. $\text{For}\,\, a,b,c\geq 0.\, {\textit{Prove that}:}$ $$\sum\limits_{cyc} \frac{(a+14)^2}{(b+4)^2}\geq \frac{3}{2} \sum\limits_{cyc} \left(\frac{a+14}{b+4}+\frac{b+4}{a+14}\right)-6\quad \quad \quad \quad \quad \left(\,\text{tthnew}\,\right)$$

Solution.

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